According to (1) we
calculate the covariance (Figure 1).

(a) Constant
c and a

(a) constant
c/a and c*a2
Figure 1: Covariances with
weighted & non in lattice constant c and a, here w-weight, cov-covariance.

(a) Si
element

(a) Mo
element

(a) V
element.
Figure 2:
Covariances with weight in lattice constant & c/a and c*a2 in
the third element.
It can be seen from
Figure 1(a,b) that a with large error has the largest covariance under both
conditions. Under both conditions, c has the lowest covariance and the highest
accuracy. According to Figure 1, the maximum error is ca2, whose
value decreases after weighting. C /a error is the minimum, with better
accuracy (Figure 2).
The Figure 2(a~c) show
that the Si correlation with ca2 is the closest so this one’s covariance is
lowest. The second correlation is a is important factor to constant. Its most
difference value is ±0.4% whose standard deviation is 63.2%. C is third one
whose value is 0.4% too but the one isn’t changeable in 1atSi. The last is c/a
which is ±1% at the end of 0 and 2Si, it explains it is the best in 1Si worst at
the end of ones. The figure 12 shows that the deviation of certain difference
is observed with c in Mo contents. The others has linear relations with Mo.
They have low deviations comparing with 46AL. As Al and ca2 is almost same, it
explains Al and this item is very approaching both in covariance and variance
status. They have consistency with the item like in weight state. They have
dependence with the item strongly. As it is known that anisotropic lattices of
c and a cause the anistrope mechanical properties according to c and a direction
and related directions. The Figure 2(c) explains V has dependency on Al. The
values increase with V element. V can play the concentration changes in 46Al
base. Maybe it plays resolution strength. The resolution includes V content and
maintains high temperature B phase which play roles of strength result in high
strength and ductility respectively. But it has high deviation ie. Dependency
in 3V. From Figure 2 it shows that a? c and c/a is low deviation relatively
with ca2. It explains that it will affect a and c primarily and then others.
Here ca2 is the highest and then c in 1V alloy. It may shows that the good
consistent with TiAl-3V and deficiency in 1V.
The
linear regression equation between c/a and Al
It is supposed that the
function f(X,Y)=0 is a linear equation. In order to find the specific
relationship between lattice constant and Al from the physical meaning, the
reason and correlation degree of the phenomenon of inadequate ductility of
metal at room temperature were found out. So we use the least square method to
calculate this linear regression equation. According to the least square
method, set the function f(X,Y)=0, X=c/a and Y=Al% above
(2)
It has
(3)
Partial derivatives to a
there is
(4)
Partial derivatives to b
it has
(5)
Above two formula is zero
if they are minimum there is
(6)
And
(7)
Calculate a and b there
is
(8)
Due to
(9)
(10)
With these two formula it
has
a=2.06, b=-0.0025
The linear regression
equation is as below
(11)