As seen in Table 1
the elastic modulus was decreased to15*cos2 (f) Gpa. The m changes in 0.09 for {111}
<011] and {011} <11(—) 1(—)], {111} <112(—)] respectively (Table 1).
The of LnK changes in 5.17~5.87 correspondingly. From them the m should
approach 0.1 nearly with varied dislocations. As shown in Table 2 when the
elastic modulus was 150Gpa the strain rate sensitivity exponent m will increase
to 0.091 in the strain rate of 1.25E-02 (Table 2). As the strain rate was high
the m was low in {111} <011]. They had shown that low rate cause high m.
That would be decreased as the elastic modulus was low to 15GPa. They had shown
that high strain rate because low m. That may be another reason. As seen in
Table 2 the trend of rate could be found. The m may decrease as both the rate
and elastic modulus were low. The m was calculated as follow in Table 1, they
were concluded as below. Slight changes were found in m but in K the value was
more different than n; that may be concluded as the Schmid factor. But no more
difference will be explained for calculated method in particular. There may be
varied in terms of main role of slip direction that means we shall pay more
attention to the important direction. The low n was the reason for small slope,
ie. Small stress raised. The m will be 0.09~0.1 approximately in the whole
slips. A little influence on slip. The course would be through that elastic
modulus was to multiply square cos? for elastic modulus. As shown in Table 3
the m of 0.167 in the rate of 1.25E-00 was higher than 0.09 in the rate of
1.25E-02 in the {011} <111(—)] while 6.31 of LnC was larger than 5.87
respectively (Table 3). That means larger stress happened on this twins in high
strain rate. The condition should be presumed that the [001] was growth
direction, however there might be some direction deviations between the actual
growth and [001]. In this paper the same tensile force with the deviated
direction that also might be depended on the actual growth direction could play
role in specimens. It should be dependent on the actual growth direction could
play role in specimens. That also might be depended on the lamellar direction.
The variation should fit to the analysis well under vary directions according
to the slip systems. As shown in Table 4 in the case of 11° that would have
high Schmid factor but in the case of 22° they
might approach virtual Schmid factor 0.356 while the 0.524 of 11° was gained in
{111(—)}<011(—)] (Table 4). That cause the low Schmid factor under 22°. The low one of
0.219 to compare with the high 0.424 in {011} <111(—)] indicate the less
resistance to plasticity. The {111(—)} <011(—)] that may be higher than the
{011} <111(—)].
The highest values
was obtained in {111} <112(—)], they were 0.594 in 11° and 0.453 in 22°. The strain
sensitivity exponent m was 1.25E-4, and detail course will be in terms of
equations. As shown in Table 5 the yield stress of TiAl is 318Mpa for TiAl
alloys (Table 5). The elongation of 2.3% was the experimental value with the
regulated method which decreased the error causing in the experiment. The E of
binary Ti3Al in computation would be 150Gpa for TiAl alloys. The deviation to
the reference was very small as 0.001~0.002nm. In Table 5 it showed the
constant and physical to compare with reference [5]. The value has been
approached approximately. The lattice constants also approached the reference
[6]. It showed that values of yield stress was higher than that of binary’s in
all the orientations, though the dependence of yield stress was mostly the same
as both specimens existent to the compressive axis. The easy type of
deformation namely shear deformation parallel to the lamellar boundary occurs
when it was tested in orientation with inter mediation angles. So the
difference in deformed’ does not exist. Meanwhile the hard type of specimens
i.e. shear deforming across the boundaries happens to in both binary and
ternary specimens. Hence it was supposed that the promotion of tensile
ductility of specimens with orientation B2 had relation to the fractures. The m
may decrease as both the rate and elastic modulus were low. As for the
parameters in Table 4, the Schmid factor as seen in Figure 1 was checked for
the main reason was the mathematical way. Here ?s was the stress, ? was the
angle between tensile axis and slip direction. The condition should be presumed
that the [001] was growth direction, however there might be some direction
deviations between the actual growth and [001]. In this paper the same tensile
force with the deviated direction that also might be depended on the lamellar
direction. It should be dependent on the actual growth direction could play
role in specimens that also might be depended on the lamellar direction. The
lattice constant of c/a has 1.017, on the basis of value that c has 0.407 and a
has 0.401nm for g.
[110]a/2?[111]a/3+[112(—)]a/6+SISF ?4?
Here a Frank partial
was [111]/3 and Shockley partial was [112]/6 bound a loop. In terms of the
calculation of anisotropic elastic line energies, dissociation was feasible as
the Shockley partial which was the edge or a mixed character. SISF was the super
intrinsic stacking fault energy. It is found that the Frank partial one was
easily formed than Shockley partial one from the Table 4 because of its low
value. Then the unit dislocation is
between them. The effective forming turn is Frank partial dislocation >unit
dislocation >Shockley partial one. That Frank partial dislocation will be
formed as many as possible was mainly emphasized in TiAl material. On the other side Shockley partial one was
hard formed. Unit one will stand between them to play a certain role in the
material.
a/2[101(—)] ?[112(—)]a/6+[21(—)1(—)]a/6+Fault?5?
a/2[01(—)1]?[12(—)1]a/6+[1(—)1(—)2]a/6+Fault ?6?
The dislocation
moving direction were consistent with Burgers vector. The planes of their
movement would be existent with Burgers vector and dislocation line. According
to plane and directions for movement of atoms that were limited, it was defined
that they would have taken place under atomic density with place of mostly
high. The yield of material took effect in the atomic structure highly, and the
work hardening could be affected by dislocation density. The full dislocation
on {001} had been existed in two part resolved dislocations. The true stress
and strain in poly crystals like Fcc could be expressed as ?=K ? m. The true
stress had one of mechanical features which was sensitive to strain rate. True
strain will be increased in terms of high m. with increasing m the true stress
increases to enhance deformation rate ?. Under tensile ? was increased so the
high elongation will be obtained (Figure 3). As for general metal m was
0.02~0.2. To poly crystals deformation of grain boundary slip will take big
role. Under the assumption those states were isothermal, heat generation and
heat transfer were not taken into account, plastic deformation by various
asymmetric processes [7,8].